Algebra 2Superchallenge ShareAlgebra 2 · Superchallenge problemEvaluate∑k=1261k23+k(k+1)3+(k+1)23.\sum_{k=1}^{26} \dfrac{1}{\sqrt[3]{k^2} + \sqrt[3]{k(k + 1)} + \sqrt[3]{(k + 1)^2}}.k=1∑263k2+3k(k+1)+3(k+1)21.Check Show answer Walk through it step by step Practice more like this