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Number TheoryChallengeFactors & Multiples

Factors & Multiples · Challenge problem

Write 100!100! as a product of primes, 100!=2a23a35a5⋯97a97100! = 2^{a_2} 3^{a_3} 5^{a_5} \cdots 97^{a_{97}}. Find the sum of all the exponents, a2+a3+a5+⋯+a97a_2 + a_3 + a_5 + \cdots + a_{97}.