Precalculus · Hard problem

The function $f(x)=\dfrac{(x-1)(x-2)(x+3)}{(x-2)(x+1)(x-5)}$ has a hole at $x=2$ with height $h$, and vertical asymptotes at $x=-1$ and $x=5$. Find $h$ plus the sum of the two vertical-asymptote locations.