MathCastle
PrecalculusChallenge

Precalculus · Challenge problem

The rational function f(x)=ax+42x+bf(x)=\dfrac{ax+4}{2x+b} (defined wherever 2x+b≠02x+b\ne0) satisfies f(f(x))=xf(f(x))=x for every xx in its domain for which f(x)f(x) is also in the domain. Given also that f(1)=−7f(1)=-7, find abab.

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