Multivariable CalculusEasyLines & Planes in Space ShareLines & Planes in Space · Easy problemThe plane through the point (1,2,3)(1, 2, 3)(1,2,3) with normal vector ⟨2,−1,4⟩\langle 2, -1, 4\rangle⟨2,−1,4⟩ has equation 2x−y+4z=D2x - y + 4z = D2x−y+4z=D. Find DDD.Check Show answer Walk through it step by step Practice more like this Review this concept