Multivariable CalculusEasyLines & Planes in Space ShareLines & Planes in Space · Easy problemThe line through (1,4,−2)(1, 4, -2)(1,4,−2) parallel to ⟨3,−1,2⟩\langle 3, -1, 2\rangle⟨3,−1,2⟩ has symmetric equations x−13=y−a−1=z−b2\dfrac{x-1}{3} = \dfrac{y-a}{-1} = \dfrac{z-b}{2}3x−1=−1y−a=2z−b. Find a+ba + ba+b.Check Show answer Walk through it step by step Practice more like this Review this concept