Partial Derivatives & the Gradient · Challenge problem

Near $(u,v) = (1,2)$ the equations $x = u + v^2$ and $y = u^2 + v$ can be solved for $u$ and $v$ as differentiable functions of $x$ and $y$; the point $(u,v) = (1,2)$ corresponds to $(x,y) = (5,3)$. Find $\dfrac{\partial u}{\partial x}$ at $(x,y) = (5,3)$.