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Multivariable CalculusSuperchallengeDouble Integrals

Double Integrals · Superchallenge problem

Evaluate ∫01 ⁣∫01dx dy1−x2y2\displaystyle\int_0^{1}\!\int_0^{1}\dfrac{dx\,dy}{\sqrt{1 - x^2y^2}}. You may use ∫0π/2ln⁡(sin⁡t) dt=−π2ln⁡2\displaystyle\int_0^{\pi/2}\ln(\sin t)\,dt = -\dfrac{\pi}{2}\ln 2. Give an exact answer.