Multivariable CalculusEasyDouble Integrals ShareDouble Integrals · Easy problemWhich iterated integral is equal to ∫01 ∫x21f(x,y) dy dx\displaystyle\int_0^{1}\!\int_{x^2}^{1} f(x,y)\,dy\,dx∫01∫x21f(x,y)dydx for every continuous fff?A∫01 ∫y1f(x,y) dx dy\displaystyle\int_0^{1}\!\int_{\sqrt{y}}^{1} f(x,y)\,dx\,dy∫01∫y1f(x,y)dxdyB∫01 ∫y21f(x,y) dx dy\displaystyle\int_0^{1}\!\int_{y^2}^{1} f(x,y)\,dx\,dy∫01∫y21f(x,y)dxdyC∫01 ∫0yf(x,y) dx dy\displaystyle\int_0^{1}\!\int_0^{\sqrt{y}} f(x,y)\,dx\,dy∫01∫0yf(x,y)dxdyD∫01 ∫0y2f(x,y) dx dy\displaystyle\int_0^{1}\!\int_0^{y^2} f(x,y)\,dx\,dy∫01∫0y2f(x,y)dxdyCheck Show answer Walk through it step by step Practice more like this Review this concept