CalculusSuperchallengeLimits and Continuity ShareLimits and Continuity · Superchallenge problemEvaluate limx→01+tanx−1+sinxx3\displaystyle\lim_{x\to 0}\dfrac{\sqrt{1+\tan x}-\sqrt{1+\sin x}}{x^3}x→0limx31+tanx−1+sinx.Check Show answer Walk through it step by step Practice more like this Review this concept