CalculusSuperchallengeLimits and Continuity ShareLimits and Continuity · Superchallenge problemWithout using derivatives, evaluate limx→0tan2x−2sinxx3\displaystyle\lim_{x\to 0}\dfrac{\tan 2x-2\sin x}{x^3}x→0limx3tan2x−2sinx.Check Show answer Walk through it step by step Practice more like this Review this concept