CalculusSuperchallengeLimits and Continuity ShareLimits and Continuity · Superchallenge problemFind limn→∞∏k=1n(1+kn2)=limn→∞(1+1n2)(1+2n2)⋯(1+nn2)\displaystyle\lim_{n\to\infty}\prod_{k=1}^{n}\left(1+\dfrac{k}{n^2}\right)=\lim_{n\to\infty}\left(1+\dfrac{1}{n^2}\right)\left(1+\dfrac{2}{n^2}\right)\cdots\left(1+\dfrac{n}{n^2}\right)n→∞limk=1∏n(1+n2k)=n→∞lim(1+n21)(1+n22)⋯(1+n2n).Check Show answer Walk through it step by step Practice more like this Review this concept