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CalculusEasyLimits and Continuity

Limits and Continuity · Easy problem

Use the special trigonometric limit lim⁡u→0sin⁡uu=1\displaystyle\lim_{u\to0}\dfrac{\sin u}{u}=1 to evaluate lim⁡x→0sin⁡7xx\displaystyle\lim_{x\to 0}\dfrac{\sin 7x}{x}.