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CalculusEasyLimits and Continuity

Limits and Continuity · Easy problem

A dropped object's height above the ground is h(t)=100−5t2h(t)=100-5t^2 meters, tt in seconds. Find the object's instantaneous velocity (in m/s) at t=2t=2 by working out what h(t)−h(2)t−2\dfrac{h(t)-h(2)}{t-2} approaches as t→2t\to2.