MathCastle
TrigonometryHard

Trigonometry · Hard problem

In △ABC\triangle ABC (sides aa, bb, cc opposite angles AA, BB, CC), the sides and angles satisfy acos⁡B+bcos⁡A=2ccos⁡Ca\cos B + b\cos A = 2c\cos C. If a=5a = 5 and c=7c = 7, find bb.

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