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Linear AlgebraHardVector Spaces & Bases

Vector Spaces & Bases · Hard problem

Let f(p)=p(0)+p′(0)+p′′(0)f(p) = p(0)+p'(0)+p''(0) for p∈P2p\in P_2. There is exactly one p∈P2p\in P_2 with f(p)=1f(p)=1, p(2)=0p(2)=0, and p(−2)=0p(-2)=0. Find p(3)p(3).