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Linear AlgebraEasyOrthogonality & Least Squares

Orthogonality & Least Squares · Easy problem

Apply one step of Gram–Schmidt to v1=(1,1,0)\mathbf v_1 = (1, 1, 0) and v2=(2,0,1)\mathbf v_2 = (2, 0, 1) (in that order, without normalizing): w2=v2−proj⁡v1v2\mathbf w_2 = \mathbf v_2 - \operatorname{proj}_{\mathbf v_1}\mathbf v_2. Find the second entry of w2\mathbf w_2.