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Matrices & Systems · Medium problem

A company's cost matrix for January is A=(1208060150)A = \begin{pmatrix}120&80\\60&150\end{pmatrix} (rows: factory 11, factory 22; columns: materials, labor, in $10001000s) and for February is B=(1009065130)B = \begin{pmatrix}100&90\\65&130\end{pmatrix}. The company projects March costs as 2B−A2B-A (double February's pattern, then correct for January's baseline). Find the row 22, column 11 entry of 2B−A2B-A.