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Matrices & Systems · Hard problem

Matrices A=(2p03)A = \begin{pmatrix}2 & p\\0 & 3\end{pmatrix} and B=(140q)B = \begin{pmatrix}1 & 4\\0 & q\end{pmatrix} commute, meaning AB=BAAB=BA. Given that q=5q=5, find pp.