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Matrices & Systems · Challenge problem

A 3×33\times 3 matrix AA satisfies A3=3IA^3 = 3I, and the matrices II, AA, A2A^2 are linearly independent. Then A+2IA + 2I is invertible and (A+2I)−1=pA2+qA+rI(A + 2I)^{-1} = pA^2 + qA + rI for unique numbers p,q,rp, q, r. Find p+q+rp + q + r.