Linear AlgebraEasyEigenvalues ShareEigenvalues · Easy problemFind the smallest eigenvalue of A=(2510−34007)A = \begin{pmatrix}2 & 5 & 1\\0 & -3 & 4\\0 & 0 & 7\end{pmatrix}A=2005−30147.Check Show answer Walk through it step by step Practice more like this Review this concept