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Linear AlgebraSuperchallengeDiagonalization & Matrix Powers

Diagonalization & Matrix Powers · Superchallenge problem

Let A=(−455−4)A = \begin{pmatrix}-4 & 5\\5 & -4\end{pmatrix} and let x(t)\mathbf{x}(t) solve the second-order system x′′=Ax\mathbf{x}'' = A\mathbf{x} with x(0)=(10)\mathbf{x}(0) = \begin{pmatrix}1\\0\end{pmatrix} and x′(0)=(v2)\mathbf{x}'(0) = \begin{pmatrix}v\\2\end{pmatrix}. For exactly one real vv the solution stays bounded for all t≥0t \ge 0. Find vv.