Linear AlgebraSuperchallengeDiagonalization & Matrix Powers ShareDiagonalization & Matrix Powers · Superchallenge problemLet K=(2−10−12−10−12)K = \begin{pmatrix}2 & -1 & 0\\-1 & 2 & -1\\0 & -1 & 2\end{pmatrix}K=2−10−12−10−12 and let x(t)\mathbf{x}(t)x(t) solve x′=−Kx\mathbf{x}' = -K\mathbf{x}x′=−Kx with x(0)=(1,0,0)\mathbf{x}(0) = (1, 0, 0)x(0)=(1,0,0). Evaluate ∫0∞∥x(t)∥2 dt\displaystyle\int_0^\infty \lVert\mathbf{x}(t)\rVert^2\,dt∫0∞∥x(t)∥2dt.Check Show answer Walk through it step by step Practice more like this Review this concept