Linear AlgebraMediumDiagonalization & Matrix Powers ShareDiagonalization & Matrix Powers · Medium problemSolve x′(t)=Ax(t)\mathbf{x}'(t) = A\mathbf{x}(t)x′(t)=Ax(t) with A=(2112)A = \begin{pmatrix}2 & 1\\1 & 2\end{pmatrix}A=(2112) and x(0)=(31)\mathbf{x}(0) = \begin{pmatrix}3\\1\end{pmatrix}x(0)=(31). Find the first component x1(t)x_1(t)x1(t) at t=ln2t = \ln 2t=ln2.Check Show answer Walk through it step by step Practice more like this Review this concept