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Linear AlgebraMediumDiagonalization & Matrix Powers

Diagonalization & Matrix Powers · Medium problem

Solve x′(t)=Ax(t)\mathbf{x}'(t) = A\mathbf{x}(t) with A=(2112)A = \begin{pmatrix}2 & 1\\1 & 2\end{pmatrix} and x(0)=(31)\mathbf{x}(0) = \begin{pmatrix}3\\1\end{pmatrix}. Find the first component x1(t)x_1(t) at t=ln⁡2t = \ln 2.