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Linear AlgebraMediumDiagonalization & Matrix Powers

Diagonalization & Matrix Powers · Medium problem

Solve x′=Ax\mathbf{x}' = A\mathbf{x} with A=(0140)A = \begin{pmatrix}0 & 1\\4 & 0\end{pmatrix} and x(0)=(10)\mathbf{x}(0) = \begin{pmatrix}1\\0\end{pmatrix}. Find the first component x1(t)x_1(t) at t=ln⁡3t = \ln 3.