Linear AlgebraMediumDiagonalization & Matrix Powers ShareDiagonalization & Matrix Powers · Medium problemSolve x′=Ax\mathbf{x}' = A\mathbf{x}x′=Ax with A=(0140)A = \begin{pmatrix}0 & 1\\4 & 0\end{pmatrix}A=(0410) and x(0)=(10)\mathbf{x}(0) = \begin{pmatrix}1\\0\end{pmatrix}x(0)=(10). Find the first component x1(t)x_1(t)x1(t) at t=ln3t = \ln 3t=ln3.Check Show answer Walk through it step by step Practice more like this Review this concept