Linear AlgebraEasyDiagonalization & Matrix Powers ShareDiagonalization & Matrix Powers · Easy problemLet A=(4123)A = \begin{pmatrix}4 & 1\\2 & 3\end{pmatrix}A=(4213). The vector v=(11)\mathbf{v} = \begin{pmatrix}1\\1\end{pmatrix}v=(11) is an eigenvector of AAA. Find the first entry of A3vA^3\mathbf{v}A3v.Check Show answer Walk through it step by step Practice more like this Review this concept