Diagonalization & Matrix Powers · Easy problem

A $2\times 2$ matrix $A$ satisfies $A\begin{pmatrix}1\\3\end{pmatrix} = -2\begin{pmatrix}1\\3\end{pmatrix}$. The vector function $\mathbf{x}(t)$ solves $\mathbf{x}' = A\mathbf{x}$ with $\mathbf{x}(0) = \begin{pmatrix}1\\3\end{pmatrix}$. Find the second component of $\mathbf{x}(\ln 3)$.