Linear AlgebraEasyDiagonalization & Matrix Powers ShareDiagonalization & Matrix Powers · Easy problemThe matrix A=(270−3)A = \begin{pmatrix}2 & 7\\0 & -3\end{pmatrix}A=(207−3) has an eigenvector of the form (1y)\begin{pmatrix}1\\y\end{pmatrix}(1y) for the eigenvalue −3-3−3. Find yyy.Check Show answer Walk through it step by step Practice more like this Review this concept