TrigonometryChallengeInverse Trigonometric Functions ShareInverse Trigonometric Functions · Challenge problemHow many ordered pairs of positive integers (a,b)(a,b)(a,b) satisfy arctan1a+arctan1b=arctan13\arctan\dfrac{1}{a}+\arctan\dfrac{1}{b}=\arctan\dfrac{1}{3}arctana1+arctanb1=arctan31?Check Show answer Walk through it step by step Practice more like this Review this concept