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TrigonometryChallengeInverse Trigonometric Functions

Inverse Trigonometric Functions · Challenge problem

How many ordered pairs of positive integers (a,b)(a,b) satisfy arctan⁡1a+arctan⁡1b=arctan⁡13\arctan\dfrac{1}{a}+\arctan\dfrac{1}{b}=\arctan\dfrac{1}{3}?