Pre-Algebra · Hard problem

Three equal lengths of ribbon, each $t$ cm long, are laid end to end and then $8$ cm is cut from the total. A second row uses four pieces of ribbon, each $(t+2)$ cm long, laid end to end with nothing cut off. Write a simplified expression, in terms of $t$ and in the form $at+b$, for how much longer the second row is than the first.