CalculusSuperchallengeInfinite Sequences and Series ShareInfinite Sequences and Series · Superchallenge problemFor how many integers xxx does the series ∑n=1∞(n!)2n2n xn\displaystyle\sum_{n=1}^{\infty}\frac{(n!)^2}{n^{2n}}\,x^nn=1∑∞n2n(n!)2xn converge?Check Show answer Walk through it step by step Practice more like this Review this concept