CalculusSuperchallengeInfinite Sequences and Series ShareInfinite Sequences and Series · Superchallenge problemFind the exact value of ∑n=0∞(−1)n3n+1=1−14+17−110+⋯\displaystyle\sum_{n=0}^{\infty}\frac{(-1)^n}{3n+1}=1-\frac14+\frac17-\frac1{10}+\cdotsn=0∑∞3n+1(−1)n=1−41+71−101+⋯.Check Show answer Walk through it step by step Practice more like this Review this concept