Proof Writing & Problem SolvingEasy ShareProof Writing & Problem Solving · Easy problemDefine a1=3a_1 = 3a1=3 and an+1=2an−1a_{n+1} = 2a_n - 1an+1=2an−1 for n≥1n \ge 1n≥1. Induction proves an=2n+1a_n = 2^n + 1an=2n+1 (step: 2(2k+1)−1=2k+1+12(2^k + 1) - 1 = 2^{k+1} + 12(2k+1)−1=2k+1+1). What is a10a_{10}a10?Check Show answer Walk through it step by step Practice more like this