Groups and FieldsEasyHomomorphisms and Isomorphisms ShareHomomorphisms and Isomorphisms · Easy problemLet φ:Z18→Z18\varphi: \mathbb Z_{18} \to \mathbb Z_{18}φ:Z18→Z18 be φ(k)=4k mod 18\varphi(k) = 4k \bmod 18φ(k)=4kmod18. How many elements does imφ\operatorname{im}\varphiimφ have?Check Show answer Walk through it step by step Practice more like this Review this concept