Groups and FieldsEasyHomomorphisms and Isomorphisms ShareHomomorphisms and Isomorphisms · Easy problemLet φ:Z15→Z15\varphi: \mathbb Z_{15} \to \mathbb Z_{15}φ:Z15→Z15 be φ(k)=6k mod 15\varphi(k) = 6k \bmod 15φ(k)=6kmod15. How many elements does kerφ\ker\varphikerφ have?Check Show answer Walk through it step by step Practice more like this Review this concept