Groups and FieldsEasySubgroups and Cyclic Groups ShareSubgroups and Cyclic Groups · Easy problemIs H={1,3,5}H = \{1, 3, 5\}H={1,3,5} a subgroup of U(9)U(9)U(9) under multiplication mod 999?AYes, HHH is a subgroup of U(9)U(9)U(9)BYes, because 1⋅3⋅5=15≡61\cdot3\cdot5=15\equiv61⋅3⋅5=15≡6, which is a unitCYes, because every element of HHH is odd and 999 is oddDNo, HHH is not even a subset of U(9)U(9)U(9)Check Show answer Walk through it step by step Practice more like this Review this concept