Groups and FieldsEasySubgroups and Cyclic Groups ShareSubgroups and Cyclic Groups · Easy problemIs H={1,11}H = \{1, 11\}H={1,11} a subgroup of U(12)U(12)U(12) under multiplication mod 121212?AYes, HHH is a subgroupBNo, because 112≡3(mod12)11^2 \equiv 3 \pmod{12}112≡3(mod12)CNo, because HHH has only two elementsDNo, because 11∉U(12)11 \notin U(12)11∈/U(12)Check Show answer Walk through it step by step Practice more like this Review this concept