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Groups and FieldsHardConjugacy and the Class Equation

Conjugacy and the Class Equation · Hard problem

In S7S_7, let τ=(1 2 3 4)(5 6)\tau = (1\,2\,3\,4)(5\,6) (so 77 is fixed) and ρ=(3 5 6 7)(1 2)\rho = (3\,5\,6\,7)(1\,2) (so 44 is fixed) — both cycle type (4,2,1)(4,2,1). Matching corresponding cycles AND the fixed point in the order written gives σ\sigma with στσ−1=ρ\sigma\tau\sigma^{-1}=\rho. What is σ(1)+σ(7)\sigma(1)+\sigma(7)?