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Groups and FieldsEasyConjugacy and the Class Equation

Conjugacy and the Class Equation · Easy problem

In S5S_5, let τ=(1 2 3)(4 5)\tau = (1\,2\,3)(4\,5) and ρ=(2 3 5)(1 4)\rho = (2\,3\,5)(1\,4). Both have cycle type (3,2)(3,2), so they are conjugate. Matching the cycles in the order written (the 33-cycle's entries to the 33-cycle's entries, the 22-cycle's entries to the 22-cycle's entries) gives a permutation σ\sigma with στσ−1=ρ\sigma\tau\sigma^{-1}=\rho. What is σ(2)\sigma(2)?