MathCastle
Groups and FieldsSuperchallengeGroups and the Group Axioms

Groups and the Group Axioms · Superchallenge problem

On the interval (−1,1)(-1,1) define a∗b=a+b1+aba*b=\dfrac{a+b}{1+ab}. This operation makes (−1,1)(-1,1) a group with identity 00. Find the value of 12∗13∗14∗⋯∗110\tfrac{1}{2}*\tfrac{1}{3}*\tfrac{1}{4}*\cdots*\tfrac{1}{10}.