Groups and FieldsChallengeGroup Actions ShareGroup Actions · Challenge problemConjugation g⋅x=gxg−1g\cdot x=gxg^{-1}g⋅x=gxg−1 is a rule for GGG acting on itself. Which statement is right?AIt is an action only when GGG is abelianBIt is not an action, because g⋅(h⋅x)=(hg)⋅xg\cdot(h\cdot x)=(hg)\cdot xg⋅(h⋅x)=(hg)⋅xCIt is not an action, because e⋅x≠xe\cdot x\ne xe⋅x=xDIt is an action: e⋅x=xe\cdot x=xe⋅x=x and g⋅(h⋅x)=ghxh−1g−1=(gh)⋅xg\cdot(h\cdot x)=ghxh^{-1}g^{-1}=(gh)\cdot xg⋅(h⋅x)=ghxh−1g−1=(gh)⋅xCheck Show answer Walk through it step by step Practice more like this Review this concept