Number TheorySuperchallengeFactors & Multiples ShareFactors & Multiples · Superchallenge problemCompute ∑d∣360lcm (d, 360d)\displaystyle\sum_{d \mid 360} \operatorname{lcm}\!\left(d,\ \dfrac{360}{d}\right)d∣360∑lcm(d, d360), where the sum runs over all positive divisors ddd of 360360360.Check Show answer Walk through it step by step Practice more like this Review this concept