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Pre-AlgebraSuperchallenge

Pre-Algebra · Superchallenge problem

Start with the number 4040. Increase it by 12\dfrac12 of itself. Then decrease the result by 13\dfrac13 of itself. Then increase that result by 14\dfrac14 of itself, then decrease by 15\dfrac15 of itself, and so on, alternating, until the last step, which increases the current number by 1100\dfrac1{100} of itself. What is the final number?

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