Pre-AlgebraSuperchallenge SharePre-Algebra · Superchallenge problemEvaluate the product (1+13)(1+18)(1+115)(1+124)⋯(1+199)\left(1+\dfrac13\right)\left(1+\dfrac18\right)\left(1+\dfrac1{15}\right)\left(1+\dfrac1{24}\right)\cdots\left(1+\dfrac1{99}\right)(1+31)(1+81)(1+151)(1+241)⋯(1+991), where the denominators are 22−1, 32−1, 42−1, …, 102−12^2-1,\ 3^2-1,\ 4^2-1,\ \ldots,\ 10^2-122−1, 32−1, 42−1, …, 102−1.Check Show answer Walk through it step by step Practice more like this