Expressions · Superchallenge problem

A three-digit number has digits $a$, $b$, $c$ (in that order), so its value is $100a+10b+c$. Moving the first digit to the end gives the number with digits $b$, $c$, $a$, and doing it again gives $c$, $a$, $b$. The three numbers add up to $2331$. The digits of the original number are three consecutive digits in increasing order (like $3$, $4$, $5$). What is the original number?