MathCastle
Proof Writing & Problem SolvingEasy

Proof Writing & Problem Solving · Easy problem

The direct proof of x2+y2≥2xyx^2 + y^2 \ge 2xy starts from (x−y)2≥0(x - y)^2 \ge 0. Apply the same idea with y=3xy = \dfrac{3}{x}: for x>0x > 0, what is the smallest possible value of x2+9x2x^2 + \dfrac{9}{x^2}?

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