MathCastle
Proof Writing & Problem SolvingEasy

Proof Writing & Problem Solving · Easy problem

A direct proof that (x+y)2≥4xy(x + y)^2 \ge 4xy for all real x,yx, y rests on the identity (x+y)2−4xy=(x−y)2(x + y)^2 - 4xy = (x - y)^2. For x=7x = 7 and y=3y = 3, what is (x+y)2−4xy(x + y)^2 - 4xy?

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