MathCastle
Proof Writing & Problem SolvingEasy

Proof Writing & Problem Solving · Easy problem

A proof of ∣x+y∣≤∣x∣+∣y∣|x + y| \le |x| + |y| for nonzero real numbers splits into cases according to whether xx is positive or negative and whether yy is positive or negative. How many cases does it have?

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