MathCastle
Differential EquationsSuperchallengeSeries Solutions

Series Solutions · Superchallenge problem

The equation (1−x2)y′′−2xy′+20y=0(1 - x^2)y'' - 2xy' + 20y = 0 has a polynomial solution yy that is even and satisfies y(1)=1y(1) = 1. Compute ∫−11y2 dx\displaystyle\int_{-1}^{1} y^2\,dx. Express your answer as a common fraction.