MathCastle
Differential EquationsChallengeSeries Solutions

Series Solutions · Challenge problem

The equation (1−x)(2−x) y′=(x−3) y(1 - x)(2 - x)\,y' = (x - 3)\,y has singular points x=1x = 1 and x=2x = 2, so the ordinary-point theorem only guarantees that the power-series solution about 00 with y(0)=1y(0) = 1 converges for ∣x∣<1|x| < 1. Find the actual radius of convergence of that series.